-3x^2+13x-2=0

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Solution for -3x^2+13x-2=0 equation: 



-3x^2+13x-2=0

a = -3; b = 13; c = -2;
Δ = b2-4ac
Δ = 132-4·(-3)·(-2)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{145}}{2*-3}=\frac{-13-\sqrt{145}}{-6}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{145}}{2*-3}=\frac{-13+\sqrt{145}}{-6}
$

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